Databas och PHP, en tutorial
Statistik över ägare
familyName |
firstName |
antal |
summa |
snitt |
---|
Hällgren |
Johan |
2 |
288000 |
144000.00 |
Klasson |
Klas |
2 |
260000 |
130000.00 |
Fé |
Tand |
1 |
159900 |
159900.00 |
Henriks |
Anna |
1 |
18000 |
18000.00 |
Larsson |
Anders |
1 |
95000 |
95000.00 |
Tén |
Tom |
1 |
185500 |
185500.00 |
SQL
SELECT p.familyName, p.firstName, count(c.carId) AS antal, sum(c.price) summa, avg(c.price) snitt
FROM car c
INNER JOIN person p ON c.personId = p.personId
GROUP BY familyName, firstName
ORDER BY antal DESC, familyname ASC, firstName ASC;